TUGAS ORKOM

Tugas Organisasi Komputer.
Nama : Dendi PranaYuda
Jurusan : Tehnik Informatika
NPM : 43E57006095016
Kelas : Pagi
1. 14810 = 100101002 = 2248 = 9416 2. 11011112 = 1578 = 11110 = 6F16 3. 4248 = 27610 = 100 010 1002 = 11416 4. DEF16 = 5707310 = 1101 1110 1111 00012 = 1 5 7 3 6 18 5. 125,4375 = 001 010 101 , 100 011 111 101
2 Jawaban :
1. 14810 = 148 : 2 = 74 + sisa 0 = 74 : 2 = 37 + sisa 0 = 37 : 2 = 18 + sisa 1 = 18 : 2 = 2 + sisa 0 = 9 : 2 = 4 + sisa 1 = 4 : 2 = 2 + sisa 0 = 2 : 2 = 1 + sisa 0 Jadi 14810 = 100101002 14810 = 148 : 8 = 18 + sisa 4 = 18 : 8 = 2 + sisa 2 Jadi 14810 = 2248 14810 = 148 : 16 = 9 + sisa 4 Jadi 14810 = 9416 2. 11011112 = ( 1 X 26 )+( 1 X 25)+(0 X 24)+( 1 X 23)+( 1 X 22)+( 1 X 21 )+( 1 X 20) = 64 + 32 + 0 + 8 + 4 + 2 + 1 = 11110 Jadi 11011112 = 11110 11011112 =001 = 1 = 101 = 5 = 111 = 7 Jadi 11011112 = 1578 1101111 = 0110 = 6 = 1111 = F Jadi 1101111 = 6F16 3. 4248 = ( 4 X 82)+( 2 X 81 )+( 4 X 80) = ( 4 X 64 )+( 2 X 8 )+( 4 X 1 ) = 256 + 16 + 4 = 27610 Jadi 4248 = 27610 4248 = 4 = 100 2 = 010 4 = 100 4248 = 100 010 10010 Jadi 4248 = 100 010 10010 4248 = 16 Di konversikan dulu ke biner menjadi 100 010 10010 1 0001 0100 = 11416 4. DEF116 = 10 DEF116 = ( D16 x 163 ) + ( E16 x 162 ) + ( F16 x 161 ) + ( 1 x 160 ) = ( 1310 x 4096 ) + ( 1410 x 256 ) + ( 1510 x 16 ) + (110 x 1 ) = 53248 + 3584 + 240 + 1 = 5707310 Jadi DEF116 = 5707310 DEF1 16 = 2 D E F 1 = 1101 1110 1111 00012 Jadi DEF116 = 1101 1110 1111 00012 DEF1 = 2 Di konversikan dahulu ke biner menjadi 1101 1110 1111 00012 1 101 111 011 110 001 = 1 5 7 3 6 18 Jadi DEF116 = 1 5 7 3 6 18 5. 125,437510 = 001 010 101 , 100 011 111 1012